Optimal. Leaf size=193 \[ \frac{i c^4 \sqrt{c-i c \tan (e+f x)}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac{i c^3 \sqrt{c-i c \tan (e+f x)}}{24 a^3 f (c+i c \tan (e+f x))^2}-\frac{i c^2 \sqrt{c-i c \tan (e+f x)}}{32 a^3 f (c+i c \tan (e+f x))}-\frac{i c^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )}{32 \sqrt{2} a^3 f} \]
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Rubi [A] time = 0.206933, antiderivative size = 193, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {3522, 3487, 47, 51, 63, 206} \[ \frac{i c^4 \sqrt{c-i c \tan (e+f x)}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac{i c^3 \sqrt{c-i c \tan (e+f x)}}{24 a^3 f (c+i c \tan (e+f x))^2}-\frac{i c^2 \sqrt{c-i c \tan (e+f x)}}{32 a^3 f (c+i c \tan (e+f x))}-\frac{i c^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )}{32 \sqrt{2} a^3 f} \]
Antiderivative was successfully verified.
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Rule 3522
Rule 3487
Rule 47
Rule 51
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \frac{(c-i c \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^3} \, dx &=\frac{\int \cos ^6(e+f x) (c-i c \tan (e+f x))^{9/2} \, dx}{a^3 c^3}\\ &=\frac{\left (i c^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{c+x}}{(c-x)^4} \, dx,x,-i c \tan (e+f x)\right )}{a^3 f}\\ &=\frac{i c^4 \sqrt{c-i c \tan (e+f x)}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac{\left (i c^4\right ) \operatorname{Subst}\left (\int \frac{1}{(c-x)^3 \sqrt{c+x}} \, dx,x,-i c \tan (e+f x)\right )}{6 a^3 f}\\ &=\frac{i c^4 \sqrt{c-i c \tan (e+f x)}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac{i c^3 \sqrt{c-i c \tan (e+f x)}}{24 a^3 f (c+i c \tan (e+f x))^2}-\frac{\left (i c^3\right ) \operatorname{Subst}\left (\int \frac{1}{(c-x)^2 \sqrt{c+x}} \, dx,x,-i c \tan (e+f x)\right )}{16 a^3 f}\\ &=\frac{i c^4 \sqrt{c-i c \tan (e+f x)}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac{i c^3 \sqrt{c-i c \tan (e+f x)}}{24 a^3 f (c+i c \tan (e+f x))^2}-\frac{i c^2 \sqrt{c-i c \tan (e+f x)}}{32 a^3 f (c+i c \tan (e+f x))}-\frac{\left (i c^2\right ) \operatorname{Subst}\left (\int \frac{1}{(c-x) \sqrt{c+x}} \, dx,x,-i c \tan (e+f x)\right )}{64 a^3 f}\\ &=\frac{i c^4 \sqrt{c-i c \tan (e+f x)}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac{i c^3 \sqrt{c-i c \tan (e+f x)}}{24 a^3 f (c+i c \tan (e+f x))^2}-\frac{i c^2 \sqrt{c-i c \tan (e+f x)}}{32 a^3 f (c+i c \tan (e+f x))}-\frac{\left (i c^2\right ) \operatorname{Subst}\left (\int \frac{1}{2 c-x^2} \, dx,x,\sqrt{c-i c \tan (e+f x)}\right )}{32 a^3 f}\\ &=-\frac{i c^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )}{32 \sqrt{2} a^3 f}+\frac{i c^4 \sqrt{c-i c \tan (e+f x)}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac{i c^3 \sqrt{c-i c \tan (e+f x)}}{24 a^3 f (c+i c \tan (e+f x))^2}-\frac{i c^2 \sqrt{c-i c \tan (e+f x)}}{32 a^3 f (c+i c \tan (e+f x))}\\ \end{align*}
Mathematica [A] time = 2.63681, size = 152, normalized size = 0.79 \[ \frac{c (\cos (3 (e+f x))-i \sin (3 (e+f x))) \left (\sqrt{c-i c \tan (e+f x)} \left (39 i \cos (e+f x)+11 i \cos (3 (e+f x))+20 \sin (e+f x) \cos ^2(e+f x)\right )+3 \sqrt{2} \sqrt{c} (\sin (3 (e+f x))-i \cos (3 (e+f x))) \tanh ^{-1}\left (\frac{\sqrt{c-i c \tan (e+f x)}}{\sqrt{2} \sqrt{c}}\right )\right )}{192 a^3 f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.052, size = 117, normalized size = 0.6 \begin{align*}{\frac{2\,i{c}^{4}}{f{a}^{3}} \left ({\frac{1}{ \left ( -c-ic\tan \left ( fx+e \right ) \right ) ^{3}} \left ({\frac{1}{64\,{c}^{2}} \left ( c-ic\tan \left ( fx+e \right ) \right ) ^{{\frac{5}{2}}}}-{\frac{1}{12\,c} \left ( c-ic\tan \left ( fx+e \right ) \right ) ^{{\frac{3}{2}}}}-{\frac{1}{16}\sqrt{c-ic\tan \left ( fx+e \right ) }} \right ) }-{\frac{\sqrt{2}}{128}{\it Artanh} \left ({\frac{\sqrt{2}}{2}\sqrt{c-ic\tan \left ( fx+e \right ) }{\frac{1}{\sqrt{c}}}} \right ){c}^{-{\frac{5}{2}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.44074, size = 818, normalized size = 4.24 \begin{align*} -\frac{{\left (3 \, \sqrt{\frac{1}{2}} a^{3} f \sqrt{-\frac{c^{3}}{a^{6} f^{2}}} e^{\left (6 i \, f x + 6 i \, e\right )} \log \left (-\frac{{\left (\sqrt{2} \sqrt{\frac{1}{2}}{\left (a^{3} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{3} f\right )} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{-\frac{c^{3}}{a^{6} f^{2}}} + i \, c^{2}\right )} e^{\left (-i \, f x - i \, e\right )}}{16 \, a^{3} f}\right ) - 3 \, \sqrt{\frac{1}{2}} a^{3} f \sqrt{-\frac{c^{3}}{a^{6} f^{2}}} e^{\left (6 i \, f x + 6 i \, e\right )} \log \left (\frac{{\left (\sqrt{2} \sqrt{\frac{1}{2}}{\left (a^{3} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{3} f\right )} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt{-\frac{c^{3}}{a^{6} f^{2}}} - i \, c^{2}\right )} e^{\left (-i \, f x - i \, e\right )}}{16 \, a^{3} f}\right ) - \sqrt{2}{\left (3 i \, c e^{\left (6 i \, f x + 6 i \, e\right )} + 17 i \, c e^{\left (4 i \, f x + 4 i \, e\right )} + 22 i \, c e^{\left (2 i \, f x + 2 i \, e\right )} + 8 i \, c\right )} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-6 i \, f x - 6 i \, e\right )}}{192 \, a^{3} f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac{3}{2}}}{{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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